If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

Difficult Level - 5%.

# project euler 001
def main():
  # declaration
  sum = 0
  
  # input
  limit = 1000
  
  # logic
  for x in range(1, limit):
    if (x % 5 == 0) or (x % 3 == 0):
      sum = sum + x
      
  # output
  print ("sum", sum)
  
# calls
main()